Ignore the fact that catch usually means exceptions which usually means some kind of failure. A piece of code is running and it just started some work that’s going to take a long time in the background, there’s no point waiting and the program can do something more useful while the stuff happens in the background. It “throws” an exception that is caught by a scheduler multiple layers of function calls up the stack. The scheduler saves the return address into a list of pending work to get back to, and then goes to find something that it can make progress on. Eventually it completes the other work and is signalled that our background task is complete. It pops the return address off the list and jumps to it, continuing the function call exactly where it left off as though nothing happened.
[info] /Users/pnf/dev/scala-playground/core/src/main/scala/fetchy/Fetchy.scala:202:10: Lifting to cats.syntax.`package`.all.toFunctorOps[[A]fetch.Fetch[F,A], (fetchy.TestBFF.FirstName, fetchy.TestBFF.LastName)](cats.Semigroupal.tuple2[[A]fetch.Fetch[F,A], fetchy.TestBFF.FirstName, fetchy.TestBFF.LastName](cats.syntax.`package`.all.toFlatMapOps[[A]fetch.Fetch[F,A], fetchy.TestBFF.FirstName](TestBFF.this.getFirstName[F](bff)(evidence$54, evidence$55))(fetch.`package`.fetchM[F](evidence$54)).self, cats.syntax.`package`.all.toFunctorOps[[A]fetch.Fetch[F,A], fetchy.TestBFF.LastName](TestBFF.this.getLastName[F](bff)(evidence$54, evidence$55))(fetch.`package`.fetchM[F](evidence$54)).self)(fetch.`package`.fetchM[F](evidence$54), fetch.`package`.fetchM[F](evidence$54)))(fetch.`package`.fetchM[F](evidence$54)).map[String](((x$13: (fetchy.TestBFF.FirstName, fetchy.TestBFF.LastName)) = {
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